2 条题解
-
-1
#include <iostream> #include <string> #include <algorithm> using namespace std; int main() { long long X; int N; cin >> X >> N; if (X == 0) { cout << 0 << endl; return 0; } string result; while (X > 0) { long long remainder = X % N; if (remainder < 10) { result += (char)('0' + remainder); } else { result += (char)('A' + remainder - 10); } X = X / N; } reverse(result.begin(), result.end()); cout << result << endl; return 0; }
- 1
信息
- ID
- 7000
- 时间
- 1000ms
- 内存
- 128MiB
- 难度
- 3
- 标签
- 递交数
- 10
- 已通过
- 7
- 上传者