2 条题解
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2
#include<bits/stdc++.h> using namespace std; int main(){ int a[5]={0},n,c; cin>>n; for(int i=1;i<=n;i++) { cin>>c; if(c<=18) a[1]++; if(19<=c&&c<=35) a[2]++; if(36<=c&&c<=60) a[3]++; if(c>60) a[4]++; } printf("%.2lf%%\n",double(a[1])/n*100); printf("%.2lf%%\n",double(a[2])/n*100); printf("%.2lf%%\n",double(a[3])/n*100); printf("%.2lf%%\n",double(a[4])/n*100); return 0; } -
-2
#include #include using namespace std;
int main() { int N; cin >> N;
int age; int count1 = 0, count2 = 0, count3 = 0, count4 = 0; // 分别对应四个年龄段 for (int i = 0; i < N; i++) { cin >> age; if (age >= 0 && age <= 18) { count1++; } else if (age >= 19 && age <= 35) { count2++; } else if (age >= 36 && age <= 60) { count3++; } else { count4++; } } cout << fixed << setprecision(2); cout << (count1 * 100.0 / N) << "%" << endl; cout << (count2 * 100.0 / N) << "%" << endl; cout << (count3 * 100.0 / N) << "%" << endl; cout << (count4 * 100.0 / N) << "%" << endl; return 0;}

- 1
信息
- ID
- 6947
- 时间
- 1000ms
- 内存
- 128MiB
- 难度
- 1
- 标签
- 递交数
- 8
- 已通过
- 6
- 上传者