1 条题解
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0
using namespace std; int main() { int n; cin >> n; int a[101][101] = {0}; int num = 1; for (int j = 1; j <= n; j++) { int h = 1; int l = j; while (h <= n && l >= 1) { if(j%2==0)a[h][l]=num++; else a[l][h]=num++; h++; l--; } } for(int i = 2; i <= n; i++) { int h = i; int l = n; while (h <= n && l >= 1) { if((n+i)%2!=0)a[h][l]=num++; else a[l][h]=num++; h++; l--; } } for(int i = 1; i <= n; i++) { for(int j = 1; j <= n; j++) { cout << a[i][j]; if(j < n) cout << " "; } cout << endl; } return 0; }
信息
- ID
- 8486
- 时间
- 1000ms
- 内存
- 512MiB
- 难度
- 5
- 标签
- 递交数
- 0
- 已通过
- 0
- 上传者